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SANJOY
- Rate £7,684
- Response 1h

£7,684/hr
Unfortunately, this tutor is unavailable
- Sanskrit
My name is sanjoy Mandal (M. A, B. A(H) in sanskrit. I have completed my M. A from Rashtriya sanskrit sansthan Deemed University (MHRD) and BA(H) from Barasat State University. Presently I pursuing
- Sanskrit
Lesson location
About SANJOY
Myself is Sanjoy Mandal BA(H) sanskrit. MA(sahitya, Vyakarana) and pursuning i am research scholar at RSKS Deemed University) and I have two time clear the NET(national Eligibility Test) With JRF. (junior Research fellowship ) and now continuing senior Research fellowship (SRF)
About the lesson
- Primary
- secondary
- Seconde
- +18
levels :
Primary
secondary
Seconde
Première
Terminale
Professional training
Facultate (Licență)
Masters
Diplomgrad
Doctorate
A1
A2
B1
B2
C1
C2
Beginner
Intermediate
Advanced
Professional
Children
- English
All languages in which the lesson is available :
English
I will provide student first theory after that i will solve the problems best on the theory then i will provide similar problem to the student and analysis the student ability. If student dont understand the problem then i will politely give him/her my lecture again and again until student understand the concept.
Rates
Rate
- £7,684
Pack prices
- 5h: £35
- 10h: £70
online
- £7,684/h
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